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php中输出json对象的值(实现方法)

栏目:PHP基础 来源: 微信小程序开发网 阅读: 2018-03-26

实例如下所示:

<!DOCTYPE html> <html> <body> <?php $$json = '{"report":{"date":"2012-04-10","content":"abcdefght"}}'; $$arr = (array) json_decode($$json,true); echo '当前日期是:'. $$arr['report']['date']; echo "<br/>"; echo '<pre>'; print_r($$arr); echo '</pre>'; foreach($$arr as $$arrvalue) { foreach($$arrvalue as $$key=>$$value) { echo "[$$key] = $$value <br />"; } } echo "<br/>"; ?> </body> </html>

<!DOCTYPE html> <html> <body> <?php $$file_exists = file_exists("json.txt"); if( $$file_exists ){ $$myfile = fopen("json.txt", "r") or die(""); $$content = fread($$myfile,filesize("json.txt")); fclose($$myfile); echo $$content; echo "<br/>"; $$arr=(array)json_decode($$content,true); echo $$arr['CSS']; echo "<br/>"; echo $$arr['AJAX']; } ?> </body> </html>

json.txt:

{ "AJAX": "Asynchronous JavaScript and XML", "CSS": "Cascading Style Sheets" }

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